Solution: The velocity of the particle is v=16(t^2) i + 4(t^3) j + (5t+2) k m/s. When t=0, x=y=z=0. Find the particle's coordinate position and the magnitude of its acceleration when t=2 s.

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The velocity of the particle is v=16(t^2) i + 4(t^3) j + (5t+2) k m/s. When t=0, x=y=z=0. Find the particle's coordinate position and the magnitude of its acceleration when t=2 s.