Solution: Water flows around a plate of width 0.500 m and length 1.00 m at a bulk velocity, v=.500 ft/s p=fluid densit (water)=1.00 g/cm^3 u=fluid vescosity (water)=.798 mPaS (note: the "m" is an SI prefix no "meter" abbreviation) The exact solution of the laminar boundary-layer equations leads to the following expression for the drag force, Fk, on a flat plate of width W and length L, wetted on both sides: Fk=1.328*(puLW^2v^3)^.5 Calculate the drag force in SI units.

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Water flows around a plate of width 0.500 m and length 1.00 m at a bulk velocity, v=.500 ft/s p=fluid densit (water)=1.00 g/cm^3 u=fluid vescosity (water)=.798 mPaS (note: the "m" is an SI prefix no "meter" abbreviation) The exact solution of the laminar boundary-layer equations leads to the following expression for the drag force, Fk, on a flat plate of width W and length L, wetted on both sides: Fk=1.328*(puLW^2v^3)^.5 Calculate the drag force in SI units.